4[1+4(5x+2y)]=0

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Solution for 4[1+4(5x+2y)]=0 equation:


Simplifying
4[1 + 4(5x + 2y)] = 0
4[1 + (5x * 4 + 2y * 4)] = 0
4[1 + (20x + 8y)] = 0
[1 * 4 + 20x * 4 + 8y * 4] = 0
[4 + 80x + 32y] = 0

Solving
4 + 80x + 32y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 80x + -4 + 32y = 0 + -4

Reorder the terms:
4 + -4 + 80x + 32y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 80x + 32y = 0 + -4
80x + 32y = 0 + -4

Combine like terms: 0 + -4 = -4
80x + 32y = -4

Add '-32y' to each side of the equation.
80x + 32y + -32y = -4 + -32y

Combine like terms: 32y + -32y = 0
80x + 0 = -4 + -32y
80x = -4 + -32y

Divide each side by '80'.
x = -0.05 + -0.4y

Simplifying
x = -0.05 + -0.4y

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